Jika f (x) = (3x² + 6) (2x-1) maka f’ (x) adalah

Jika f (x) = (3x² + 6) (2x-1) maka f’ (x) adalah

Jawaban : f'(x) = 18x² – 6x + 12

Pembahasan :
Turunan merupakan suatu fungsi yang digunakan sebagai pengukuran terhadap perubahan fungsi akibat perubahan nilai variabel.

Sifat-sifat turunan fungsi :
f(x) = a → f'(x) = 0
f(x) = x → f'(x) = 1
f(x) = ax → f'(x) = a
f(x) = ax^n → f'(x) = (a · n) · x^(n-1)

Diketahui :
f(x) = (3x² + 6)(2x – 1)

Ditanya :
f'(x) =..?

Penyelesaian :
f(x) = (3x² + 6)(2x – 1)
f(x) = (3x² · 2x) – (3x² · 1) + (6 · 2x) – (6 · 1)
f(x) = 6x³ – 3x² + 12x – 6

f(x) = 6x³ – 3x² + 12x – 6
f'(x) = (6 · 3)x^(3-1) – (3 · 2)x^(2-1) + (12 · 1)x^(1-1) – 0
= 18x² – 6x + 12x⁰ – 0
= 18x² – 6x + 12(1) – 0
= 18x² – 6x + 12

Jadi, turunan f(x) atau f'(x) diatas adalah 18x² – 6x + 12.

Rekomendasi lainnya :

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