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Cermin cekung fokusnya 50 cm,benda didepan cermin 75 cm, letak bayangan dan sifat-sifatnya :

cermin cekung fokusnya 50 cm,benda didepan cermin 75 cm, letak bayangan dan sifat-sifatnya :

a. 150 cm; didepan; nyata ; diperbesar
b. 150 cm; dibelakang; maya ; diperbesar
c. 150 cm; di depan; maya; diperkecil
d. 30 cm; dibelakang; maya; diperkecil
e. 30 cm; didepan ; nyata; diperbesar

Jawaban yang benar adalah A.

Diketahui :
f = 50 cm
s = 75 cm

Ditanya : s’ = …? sifat bayangan = …?

Penyelesaian :
Cermin cekung merupakan cermin konvergen yang mengumpulkan sinar. Jarak bayangan benda pada cermin cekung dapat dihitung menggunakan persamaan berikut.
1/s’ = 1/f – 1/s
Keterangan :
s’ = jarak bayangan (cm)
f = jarak fokus cerming (m)
s = jarak benda dari cermin (m)

Hitung letak bayangan.
1/s’ = 1/f – 1/s
1/s’ = 1/50 – 1/75
1/s’ = (3 – 2)/150
1/s’= 1/150
s’ = 150/1
s’ = 150 cm

Sifat bayangan yang terjadi pada cermin cekung dapat dilihat pada tabel di bawah ini (terlampir pada gambar).

Benda berada di ruang II yaitu di antara jarak fokus (f) dan pusat kelengkungan cermin (M) sehingga bayangan bersifat nyata, terbalik, dan diperbesar. Bayangan nyata terletak di depan cermin.

Dengan demikian, bayangan tersebut terletak pada jarak 150 cm di depan cermin dan bersifat nyata diperbesar.
Jadi, jawaban yang tepat adalah A.

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