Sebuah benda bergerak dengan kecepatan 6 m/s, lalu bergerak lagi dengan kecepatan 10 m/s. Jika massa benda 4 kg, Berapakah usaha benda tersebut?

Sebuah benda bergerak dengan kecepatan 6 m/s, lalu bergerak lagi dengan kecepatan 10

m/s. Jika massa benda 4 kg, Berapakah usaha benda tersebut?

Jawaban untuk pertanyaan ini adalah : 128 J

Pada soal diatas
Diketahui :
v1 = 6 m/s
v2 = 10 m/s
m = 4 kg

Ditanyakan :
W = …?

Pembahasan :
Usaha yang dilakukan oleh benda yang bergerak sama dengan perubahan energi kinetik pada benda tersebut.
Untuk menyelesaikan soal diatas kita menggunakan persamaan, sebagai berikut :
W = ∆Ek
dimana :
W = usaha (J)
∆Ek = perubahan energi kinetik (J)

Sehingga :
Untuk menentukan energi kinetik benda, kita gunakan persamaan :
Ek = (1/2)mv^2
dimana :
Ek = energi kinetik (J)
m = massa (kg)
v = kecepatan (m/s)

maka :
W = ∆Ek
W = Ek(2) – Ek(1)
W = (1/2)m(v2)^2 – (1/2)m(v1)^2
W = (1/2)m[(v2)^2 – (v1)^2] W = (1/2)4[(10)^2 – (6)^2] W = 2[(100) – (36)] W = 2[64] W = 128 J

Jadi, usaha pada benda adalah 128 J

Rekomendasi lainnya :

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