Tentukan nilai a, b, dan c, dari persamaan kuadrat!!!!
1) 4x²=7x
2) -6x²+10=7x+6
3) 2x (3x+5)=4
4) 5(x²+2)=2x(3x+1)
Jawab:
(1.) A = 4, B = -7, C = 0
(2.) A = 6, B = 7, C = -4
(3.) A = 6, B = 10, C = -4
(4.) A = 1, B = 2, C = -10
Penjelasan:
Bentuk persamaan kuadrat
Ax² + Bx + C = 0
(1.) 4x² = 7x
4x² – 7x + 0 = 0
Ax² + Bx + C = 0
A = 4, B = -7, C = 0
(2.) -6x² + 10 = 7x + 6
6x² + 7x + 6 – 10 = 0
6x² + 7x – 4 = 0
Ax² + Bx + C = 0
A = 6, B = 7, C = -4
(3.) 2x(3x+5) = 4
2x(3x) + 2x(5) – 4 = 0
6x² + 10x – 4 = 0
Ax² + Bx + C = 0
A = 6, B = 10, C = -4
(4.) 5(x²+2) = 2x(3x+1)
5x² + 5(2) = 2x(3x) + 2x(1)
5x² + 10 = 6x² + 2x
6x²-5x² + 2x – 10 = 0
x² + 2x – 10 = 0
1x² + 2x – 10 = 0
Ax² + Bx + C = 0
A = 1, B = 2, C = -10
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