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Tentukan jumlah suku ke 20 pertama deret 1+√2+2+2√2+ ​

Tentukan jumlah suku ke 20 pertama deret

1+√2+2+2√2+ ​

Deret Geometri

 

1 + √2 + 2 + 2√2 + ..

a = U1 = suku pertama = 1

r = rasio = U2/U1 = √2 /1 = √2

 

Jumlah n suku pertama (Sn)

Sn = a(rⁿ – 1) / (r – 1)

 

Jumlah 20 suku pertama

S20 = 1((√2)²⁰ – 1) / (√2 – 1)

S20 = (2¹⁰ – 1)(√2 – 1)/(2 – 1)

S20 = 1023 (√2 – 1)

S20 = 10232  1023

 

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