Carilah akar akar persamaan kuadrat dengan rumus a b c
3x²-2x-8=0
3x² – 2x – 8 = 0
a = 3
b = -2
c = -8
x = (-b ± √(b² – 4ac))/2a
• x = (-(-2) + √((-2)² – 4(3)(-8))/2(3)
= (2 + √(4 – (-96))/6
= (2 + √100)/6
= (2 + 10)/6
= 12/6
= 2
atau
• x = (-(-2) – √((-2)² – 4(3)(-8))/2(3)
= (2 – √(4 – (-96))/6
= (2 – √100)/6
= (2 – 10)/6
= -8/6
= -1⅓
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