modulus dari vektor a = 3i – 4j + k adalah…….
a.√22
b.√23
c.√24
d.√26
e.√29
Modulus vektor = √(i)²+(j)²+(k)²
|a| = √(3)²+(-4)²+(1)²
= √9+16+1
= √26
Modulus vektor = √(i)²+(j)²+(k)²
|a| = √(3)²+(-4)²+(1)²
= √9+16+1
= √26