Tentukan himpunan penyelesaian dari |x+4|≤8

Tentukan himpunan penyelesaian dari |x+4|≤8

Jawabannya adalah {x | -12 ≤ x ≤ 4, x ∈ R}.

Konsep yang digunakan :
📌 Jika |f(x)| ≤ a maka -a ≤ f(x) ≤ a

Perhatikan penjelasan berikut.
|x+4| ≤ 8
Maka :
-8 ≤ x+4 ≤ 8
masing-masing ruas dikurangi 4
-12 ≤ x ≤ 4

Jadi, himpunan penyelesaian pertidaksamaan nilai mutlak tersebut adalah {x | -12 ≤ x ≤ 4, x ∈ R}.

 

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