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2m-⁴ × m-³=

2m-⁴ × m-³=

Penyelesaian Soal Bagian a]

2m⁻⁴ x m⁻³ ⇒ 2m⁽⁻⁴⁺⁽⁻³⁾⁾ → Sifat I

2m⁻⁴ x m⁻³ = 2m⁽⁻⁴⁻³⁾

= 2m⁻⁷ → Sifat III

= \frac{2}{m^{7}}
m
7

2

 

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