Diketahui persamaan gelombang berjalan y=0,2sin (10π-πx per 4) y dna x dalam m, t dalam sekon. tentukan amplitudo, frekuensi, panjang gelombang, bilangan gelombang, dna ceoat rambay gelombang

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diketahui persamaan gelombang berjalan y=0,2sin (10π-πx per 4) y dna x dalam m, t dalam sekon. tentukan amplitudo, frekuensi, panjang gelombang, bilangan gelombang, dna ceoat rambay gelombang

Amplitudo gelombang 0,2 m, frekuensi gelombang 5 Hz, panjang gelombang 8 m, bilangan gelombang π/4, dan ceoat rambat gelombang 40 m/s..

Diketahui :
y = 0,2 sin (10πt – πx/4)

Ditanya : A = …? f = …? λ = …? k = …? v = …?

Penyelesaian :
Simpangan pada gelombang berjalan dirumuskan sebagai berikut.
y = ±A sin(ωt ± kx)
dengan
k = 2π /λ
ω = 2πf
Keterangan :
y = simpangan (m)
A = amplitudo (m)
k = bilangan gelombang (/m)
ω = kecepatan sudut (rad/s)
t = waktu (s)
x = jarak titik (m)
λ = panjang gelombang (m)
f = frekuensi (Hz)

+A = arah gelombang pertama kali ke atas sedangkan -A = arah gelombang pertama kali ke bawah
+kx = gelombang merambat ke kiri sedangkan -kx = gelombang merambat ke kanan

y = A sin(ωt – kx)
y = 0,2 sin (10πt – πx/4)
Berdasarkan persamaan di atas, dapat diketahui bahwa A = 0,2 m, ω = 10π rad/s, dan k = π/4.

Hitung frekuensi gelombang.
ω = 2πf
f = ω/2π
f = 10π /2π
f = 5 Hz

Hitung panjang gelombang.
k = 2π /λ
λ = 2π /k
λ = 2π /(π/4)
λ = 8 m

Hitung cepat rambat gelombang.
v = λf
v = 8(5)
v = 40 m/s

Dengan demikian, amplitudo gelombang 0,2 m, frekuensi gelombang 5 Hz, panjang gelombang 8 m, bilangan gelombang π/4, dan ceoat rambat gelombang 40 m/s.

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