Sec 330°. tan 120°. sin 315°=…

sec 330°. tan 120°. sin 315°=…

jawaban untuk soal di atas adalah √2

Ingat kembali:
sec (360⁰–A) = sec A
tan (180⁰–A) = –tan A
sin (360⁰–A) = –sin A
sec 30⁰ = (2√3)/3
tan 60⁰ = √3
sin 45⁰ = √2/2

Ingat juga:
–a × (–b) = a × b
(a/b) × c × (d/e) = (a × c × d)/(b × e)
(a × b)/c = (a/c) × b
a√b = a × √b
√a × √a = a

sec 330⁰ × tan 120⁰ × sin 315⁰
= sec (360⁰–30⁰) × tan (180⁰–60⁰) × sin (360⁰–45⁰)
= sec 30⁰ × (–tan 60⁰) × (–sin 45⁰)
= sec 30⁰ × tan 60⁰ × sin 45
= {(2√3)/3} × √3 × (√2/2)
= (2 × √3 × √3 × √2)/(3 × 2)
= (2 × 3 × √2)/6
= (6 × √2)/6
= (6/6) × √2
= 1 × √2
= √2

Jadi, hasil dari sec 330⁰ × tan 120⁰ × sin 315⁰ adalah √2

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