Diberikan cos α = 8/10 dengan α lancip. maka sin α =….

diberikan cos α = 8/10 dengan α lancip. maka sin α =….

pembahasan:

perlu diketahui bahwa:
cos = samping / miring
tan = depan / samping
sin = depan / miring

ditanya: sin α

jawab:
cos α = 8/10
sisi samping = 8
sisi miring = 10

sedangkan pada sin α yang dicari adalah sisi depan dan miringnya, oleh karena itu kita perlu mencari sisi depannya terlebih dahulu dengan cara menggunakan rumus Pythagoras

depan² = (√miring² – samping²)
depan² = (√10² – 8²)
depan² = (√100 – 64)
depan² = √36
depan = 6

maka nilai sin α adalah 6/10

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