Tentukan nilai lim X→π/3 2 sin x-tan/ 1 + 2 cos 2x​

Tentukan nilai lim X→π/3 2 sin x-tan/ 1 + 2 cos 2x​

Limit Tak Tentu

Bentuk 0/0

LHopital

 

π/3 = 180°/3 = 60°

 

lim x→π/3 (2 sin x – tan x) / (1 + 2 cos 2x)

= lim x→π/3 (2 cos x – sec² x) / (0 + 2(-2 sin 2x))

= lim x→π/3 -(2 cos x – sec² x) / 4 sin 2x

= – (2 cos 60° – sec² 60°) / (4 sin 2(60°))

= – (2 . 1/2 – 2²) / 4(1/2 √3)

= – (1 – 4) / 2√3

= 3/(2√3)

1/2 √3

 

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